What is the radius of the first orbit in hydrogen according to Bohr’s model?

Bharat Bhushan Wadhwa
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According to Bohr's model of the hydrogen atom, the radius of the first orbit (also known as the ground state) can be calculated using the following equation:

r = (n^2 * h^2 * ε₀) / (π * m * e^2)

Where:

  • r is the radius of the orbit
  • n is the principal quantum number (in this case, n = 1 for the ground state)
  • h is Planck's constant (6.626 x 10^-34 J s)
  • ε₀ is the permittivity of free space (8.85 x 10^-12 F/m)
  • m is the mass of the electron (9.11 x 10^-31 kg)
  • e is the elementary charge (1.60 x 10^-19 C)

Using these values in the equation gives:

r = (1^2 * (6.626 x 10^-34 J s)^2 * 8.85 x 10^-12 F/m) / (π * 9.11 x 10^-31 kg * (1.60 x 10^-19 C)^2)

Simplifying this expression yields a radius of approximately 5.29 x 10^-11 meters, which is known as the Bohr radius.

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